draw a schematic diagram of a circuit constituting of a battery of 3 cells 2 volt is a combination of three resistors 10 ohm 20 ohm and 30 ohm connected in parallel a plug key and ammeter all connected in series using this circuit to find the value of the following a a current through each resistor be total current in the circuit see total effective resistance of the circuit
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As per the data provided in the sum three resistors of 5Ω,10Ω and 15Ω are connected in series so the net resistance = 5Ω +10Ω+15Ω = 30Ω.
Also given that five cells of 2 V are connected in series,
So, the total voltage of the battery is 10V,according to Ohm's law
V=IR and I=V/R
On substituting resultant voltage(V) as 10 V and resultant resistance as 30Ω.
I=10 V/ 30Ω. = 3.33 ampere
Explanation:
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