Draw a schematic diagram of circuit consisting of a battery of 3 V and
three resistances of 6 Ω, 4 Ω, 5 Ω respectively joined in series with an
ammeter and a key. Find out the current in the circuit.
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Answer:
Above is the schematic diagram of the circuit
Explanation:
The Resisters are in Series connection
Therefore,
Rs= R1 + R2 + R 3
Rs = ( 6 + 4 +5 ) ohm
Rs = 15 ohm
The resistance is 15 ohm
Using Ohms law,
Given , V = 6 v, R = 15 ohm, I = ?
We know that,
V = I R
6v = I × 13 ohm
6v/15 ohm = I
I = 0.4 A
The current is 0.4 A
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