Physics, asked by tzprajan, 5 months ago

Draw a schematic diagram of circuit consisting of a battery of 3 V and

three resistances of 6 Ω, 4 Ω, 5 Ω respectively joined in series with an

ammeter and a key. Find out the current in the circuit.​

Answers

Answered by Suga7
1

Answer:

Above is the schematic diagram of the circuit

Explanation:

The Resisters are in Series connection

Therefore,

Rs= R1 + R2 + R 3

Rs = ( 6 + 4 +5 ) ohm

Rs = 15 ohm

The resistance is 15 ohm

Using Ohms law,

Given , V = 6 v, R = 15 ohm, I = ?

We know that,

V = I R

6v = I × 13 ohm

6v/15 ohm = I

I = 0.4 A

The current is 0.4 A

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