Draw a triangle ABC in which,AB = 4cm, BC = 6cm and AC = 9cm. construct a triangle similar to ΔABC with scale factor 3/2.
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Answer:Step-by-step explanation:
- draw a line segment BC=6 cm
- with center B and radios 4 cm draw an arc.
- with center C and radios is 9 cm draw an other arc which intersect the previous A
- join AB and CA.ABC is required triangle
- Through B,draw an acute angle <CBX on the side opposite to vertex A
- location three B1, B2 and B3 on bx such as that BB1 =B1B2=B2B3
- join B2C
- draw B3C||B2C intersecting line segment BC at C
- Draw C' A'||CA intersecting the extended lineament BA to A'
- triangle A' BC' is required triangle (A'BC'~triangle ABC)
Explanation
B3C'||B2C
BC/CC=2/1
BC'/BC =BC+CC /BC=1+CC/BC=1
AGAIN
CC'||CA
TRIANGLE ABC~TRIANGLE A'BC'
A'B/AB=BC'/BC=C'C/AC=3/2
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