Question

Draw a triangle ABC in which BC=5•2cm,angleB=100degree and angleA=60degree.Draw the perpendicular bisector
from B to AC.​

Answer 1

Answer:

Step-by-step explanation:

1. Draw a horizontal line. Using a scale or a compass (using arcs) locate B and C such that BC= 5.2 cm.

2. At B, draw a line at 60 deg inclined to BC, using a protractor.

∠C = 180 - ∠A - ∠B = 20°

3. Draw a line inclined at 20 deg. to CB, at point C using a protractor. This line is to cut the earlier line from B.

4. The point of intersection is point A.  The angle at A will be 100 deg.  

done.

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