Question

Draw a triangle ABC in which BC = 8 cm and angle B=50° & angle A=50° also bisect angle A and angle C

Answer 1

first draw a line bc of 8 cm which will be the base of ur triangle
then with the help of a protector mark 50° from point b and c then joint it u will get an isosceles triangle
now use a rounder take a small lenght make an arc at C now measure the lenght of ur arc nd cut from the two points where u made the arc at first ten joint the point to the point c similarly do it with point A

Answer 2

Therefore $ABC$ is required triangle.

Step-by-step explanation:

Given;

$BC=8$ cm , $\angle B=50$ degree and $\angle A=50$

We know for a $\bigtriangleup ABC$,

$\angle A+\angle B+\angle C=180$

⇒$\angle C=180-\angle A-\angle B$

⇒$\angle C=180-50-50$   (By plug the values)

⇒$\angle C=80$

Step 1=Draw line $BC$(8 cm)

Step 2=From point $B$ draw $50$ degree line  $BX$

Step 3=From point $C$ draw $80$ degree line $CY$ which cuts $BX$ at $A$

Step 4=And also bisect the angle $A$ and $C$ as soon in figure.

Now $ABC$ is required triangle.