Question

Draw a triangle ABC in which BC = 8 cm, ZB = 50° and ZA = 50°. Also bisect ZA and ZC.​

Answer 1

Answer:

First draw a line segment BC=8 cm.

Then, draw 50° at B and extend the ray.(Now if A=50 and B is also 50°, then C=80°.by Angle Sum Property of a Triangle.)

Now draw 100° at C and extend it

The point where B and C meet is A.And finally bisect angle A and C.(A will be 25° & C will be 40°).

Answer 2

Hence ABC is required Triangle

$\huge\boxed{\fcolorbox{red}{pink}{Step by step}}$

Given;

BC=8BC=8 cm , \angle B=50∠B=50 degree and \angle A=50∠A=50

We know for a \bigtriangleup ABC△ABC ,

\angle A+\angle B+\angle C=180∠A+∠B+∠C=180

⇒\angle C=180-\angle A-\angle B∠C=180−∠A−∠B

⇒\angle C=180-50-50∠C=180−50−50   (By plug the values)

⇒\angle C=80∠C=80

Step 1=Draw line BCBC (8 cm)

Step 2=From point BB draw 5050 degree line  BXBX

Step 3=From point CC draw 8080 degree line CYCY which cuts BXBX at AA

Step 4=And also bisect the angle AA and CC as soon in figure.

Now ABC is required triangle.