Draw a triangle ABC with side base BC= 8 cm & altitude 4 cm, & then construct
another triangle whose sides are 5/3 times the corresponding sides of triangle ABC.
Answers
Answer:
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Answer
Draw a base line BC=8\ cmBC=8 cm using scale.
Draw a perpendicular line from mid point of the line BCBC like XD\perp BCXD⊥BC
DD as center and 4\ cm4 cm as radius draw an arc on line DXDX which is known as AA
Join ABAB and ACAC
Below the line BCBC draw any angle like \angle CBY=\theta∠CBY=θ
Divide the line BYBY into 88 equal parts like B_{1},B_{2},......,B_{8}B
1
,B
2
,......,B
8
Join B_{3}CB
3
C
Draw a point B_{8}B
8
draw a parallel line with B_{3}CB
3
C to intersect BCBC extended at C^{'}C
′
Draw a point B_{8}B
8
draw a parallel line with B_{3}CB
3
C to intersect BCBC extended at C^{'}C
′
Draw a line through C^{'}C
′
parallel to the line ACAC to intersect ABAB extended at A^{'}A
′
Now, \triangle A^{'}BC^{'}△A
′
BC
′
is the triangle whose sides are \frac{5}{3}
3
5
to the \triangle ABC△ABC
