Draw a triangle ABC with side BC =6.5cm, angle B=30, angle A=105 . Then construct another traingle whose sides are 3/4 times the corresponding sides of the triangle ABC.
Answers
Answer:
Δ ABC is constructed
Step-by-step explanation:
BC =6.5cm,∠B=30°, ∠A=105°
∠A + ∠B + ∠C = 180°
=> 105° + 30° + ∠C = 180°
=> ∠C = 45°
Step 1 : Draw line segment BC = 6.5 cm using ruler
Step 2 : Draw an angle of 30° at B using protector
Step 3 : Draw an angle of 45° at C using protector
Step 4 : Find intersection point A of both angles
Step 5 : Join AB & AC
Δ ABC is constructed
Find Bisector of BC at point D
then find bisector of CD at E
now BE = (3/4)BC
Now in step 1 , take length = BE
and repeat the step from 2 to 5
Answer:
Δ ABC is constructed
Step-by-step explanation:
BC =6.5cm,∠B=30°, ∠A=105°
∠A + ∠B + ∠C = 180°
=> 105° + 30° + ∠C = 180°
=> ∠C = 45°
Step 1 : Draw line segment BC = 6.5 cm using ruler
Step 2 : Draw an angle of 30° at B using protector
Step 3 : Draw an angle of 45° at C using protector
Step 4 : Find intersection point A of both angles
Step 5 : Join AB & AC
Δ ABC is constructed
Find Bisector of BC at point D
then find bisector of CD at E
now BE = (3/4)BC
Now in step 1 , take length = BE
and repeat the step from 2 to 5