Question

Draw a triangle ABC with side BC = 6 cm, AB = 5 cm and ANGLE ABC = 60°. Then construct
a triangle whose sides are 3/4
of the corresponding sides of the triangle ABC.
PLZ SEND JUSTIFICATION ONLY ......
DONT NEED CONSTRUCTION STEPS....​

Answer 1

Triangle not exist whose sum of all angle is 60

Answer 2

Answer:

ABC.

1. Draw a line segment BC of 6 cm. Draw an arc of any radius while taking B as centre. Let it intersect line BC at point O. Now taking O as centre draw another arc to cut the previous arc at point O'. Joint BO' which is the ray making 60° with line BC.

2. Now draw an arc of 5 cm. radius, while taking, B as centre, intersecting extended line segment BO' at point A. Join AC. DABC is having AB = 5 cm. BC = 6 cm and ABC = 60°.

3. Draw a ray BX making an acute angle with BC on opposite side of vertex A.

4. Locate 4 points (as 4 is greater in 3 and 4). B1, B2, B3, B4 on line segment BX.

5. Join B4C and draw a line through B3, parallel to B4C intersecting BC at C'.

6. Draw a line through C' parallel to AC intersecting AB at A'. DA'BC' is the required triangle.

Step-by-step explanation: