Math, asked by sbmplmanish16, 10 months ago

Draw a triangle ABC with side BC=6cm, AB=5cm and angleABC=60°.Then construct a triangle whose sides are ¾ of the corresponding sides of the triangle ABC. write the steps of construction.​

Answers

Answered by neerajkhaden
0

Step-by-step explanation:

see owsal page no. 220 Qn. no. 8 for full answer

Answered by ekta9860
0

Step-by-step explanation:

1 Draw triangle ABC with BC as base .

2 Draw an acute angle CBX.

3 Cut the ray BX in 4 parts with same radius.

4 Name them B1,B2,B3,B4

5Join B4 with C.

6 Now take any radius and Mark an arc at B4

with same radius Mark an arc at B3

7 Measure the arc made at B4 and Mark an arc on the arc at B3

8 Extend B3 to meet BC through the acrs

9 Now follow the same procedure as done in step 6to 8.

10 Join the points to meet line AB and name it A1

11 A1BC1 is the required triangle

hope you will understand

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