Draw a triangle ABC with side BC= 7 cm, B = 45°, A= 105°. Then construct a
triangle whose sides are 4/ 3 times the corresponding sides of triangle ABC.
Answers
Answered by
9
Answer:
Step-by-step explanation:
(A) +(B) +(C) =180
105+45+(C) =180
150+(C) =180
(C) =180-150
(C) =30
.. The required triangle is A'BC'
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Anonymous:
how did u draw 105 in the angle A
I didn't drown 105 angles I used angle sum property of a triangle and found angle b and drawed angle B
sry angle C
Ok
I marked u as the brainliest
Answered by
4
Answer:
Step-by-step explanation:
(A) +(B) +(C) =180
105+45+(C) =180
150+(C) =180
(C) =180-150
(C) =30
.. The required triangle is A'BC'
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