Question

draw a triangle ABC with side BC equal to 7 cm Angle B equal to 45 degree angle equal to 105° and construct a triangle whose sides are 4 by 3 times the corresponding sides of triangle ABC

Answer 1

1. Draw a triangle ABC having side BC = 7 cm, ∠B = 45, ∠C = 30

2. Now, draw a ray BX making an acute angle with BC on the opposite side of vertex A

3. Now, locate 4 points B1 ,B2 , B3 ,B4 on BX

4. Join B3 X and draw a line through B4 parallel to B3 C intersecting extended BC at C1

5. Now, through C1 , draw a line parallel to AC intersecting extended line segment at C1 .

Now, triangle A1 B1 C1 is the required triangle.