Question

draw a triangle ABC with sides BC =6cm AB = 5cm and angle ABC=60^ then construct a triangle whose sides are 3/4 of the corresponding sides of the triangle ABC Justify

Answer 1

Answer:

Step-by-step explanation:

Draw a triangle ABC with sides BC =6cm AB = 5cm and angle ABC=60^ then construct a triangle whose sides are 3/4 of the corresponding sides of the triangle ABC Justify

sides are 3/4 of the corresponding sides of the triangle ABC

Let say triangle PQR

ΔPQR ≅ ΔABC

PQ/AB = QR/BC  = PR/AC = 3/4

PQ = (3/4)*5 = 3.75 cm

QR = (3/4)*6 = 4.5 cm

∠PQR = ∠ABC   ( corresponding angles are equal in similar triangles)

∠PQR = 60°

First Draw PQ = 3.75 cm

then at angle of 60° draw aline QR = 4.5 Cm

then join R & P with straight line

Required Triangle is drawn.