angle of elevation of the top of a building from the foot of a tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 60° if the height of the building is 15 M find the height of the tower
deepakkadian6:
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•Let the height of the tower be Xm.
The height of building= 15 m
So by tan30° ,
p/b = 15/b = 1/√3
b= 15√3m
. Now, the bases of both the triangles is same.
So for the height of tower,
tan60° = √3 = X/15√3.
X = 15×√3×√3
X = 45m
Hopefully it will help you .!!
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