Draw a triangle def such that def with de 4cm df 6cm and def 90°
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See the picture part
Step-by-step explanation:
Steps of construction: 1. Draw a line segment EF of length 6 cm. 2. With E as center, draw an arc of radius 4 cm. 3. With F as center, draw an arc of radius 4 cm intersecting the previous arc at D. 4. Join DE and DF to get the desired triangle DEF. 5. By measuring we get, ∠E= ∠F= 40°.
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