Draw a triangle of sides 4 5 6 cm and draw a square of the same area
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Area of the triangle is half base multiplied by the altitude.draw a line AB having 4 cm .draw an arc of length 5cm centered at A and an arc 6cm centered at B.these two arcs meet at a point and is taken as the 3 rdvertex of the triangle.thus we get triangle.from the vertex C draw perpendicular to the base AB and foot of the perpendicular is taken as D.measure CD which is the altitude.draw a semicircle having diameter half base that is 2 plus altitude we got.let the diameter be XY.mark a point 2cm from X.let it be P.at P draw a perpendicular to the diameter to meet the semi circle at Q.then draw a square having side PQ which is the required square.
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