Draw a triangle of sides 6 cm and 3 cm and draw asquare of the same area
Answers
Answer:
Steps of Construction for triangle:
1. Draw a line segment BC of length 5cm.
2. Measure distance of 6 cm in compass. Taking B as centre draw an arc.
3. Taking C as centre with same distance and draw another arc.
4. Both the arcs intersect each other; name that point of intersection as A.
5. Required triangle ABC is drawn.
Area of ABC can be calculated using Heron's formula.
s=
2
5+6+6
=
2
17
cm
Area △ABC=
2
17
(
2
17
−5)(
2
17
−6)(
2
17
−6)
=
2
17
×
2
7
×
2
5
×
2
5
=13.6cm
2
Area of Square =(side)
2
13.63=(side)
2
side=3.7cm
(B)
Steps of Construction for square:
1.Draw segment BC of length 3.7cm.
2.Draw a line perpendicular to BC through B.
Measure a distance of 3.7 cm in compass and cut this line at point A.
3.Draw a line perpendicular to BC through C.
Measure a distance of 3.7 cm in compass and cut this line at point D.
4.Join AB, CD and AD.
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