Question

स्टोन ओपन कीजिए थ्रोन विद वेलोसिटी ऑफ 20 मीटर पर सेकंड अट रोहतक फ्रोजन सरफेस ऑफ ए लेक एंड कम्स टो रेस्ट आफ्टर ट्रैवलिंग ए डिस्टेंस ऑफ 50 मीटर व्हाट इज द कॉस्ट ऑफ फ्रिक्शन बिटवीन द स्टोन एंड आइस

Answer 1

ANSWER

Before we proceed we have to make a free body diagram of the stone-ice system. In the figure, we are seeing that frictional force is acting in leftward while the stone in moving rightward direction. One thing we have to fix in our mind that frictional force will always act opposite to the direction of motion of the body.

Now on resolving the forces,

f−ma or f=ma ------(1)

also form the equation of motion v

2

=u

2

+2as, here final velocity is zero,so v=0

u

2

=−2as

a=

2s

−u

2

=−

2×50

20

2

=−4

sec

2

m

on substituting the given data in equation(1)

f=1×(−4)=−4N

Hope it help you

fire write the solution and then make the diagram