Question

draw a triangle pqr in which pq=7, qr = 3cm and rp = 4 CM. is the construction of triangle possible?

Answer 1

Answer:

No, the construction of this triangle is not possible

Step-by-step explanation:

Given triangle pqr, where

pq = 7 cm,

qr = 3cm &

rp = 4cm

as we can see,

pq = qr + rp

i.e., sum of the two sides of this traingle is equal to the third side.

But, basic principle of the triagle says taht,

Sum of any two sides of the triangle > third side.

This contradicts with the given size of the triangle (pqr)

∴ We cannot construct the Δpqr

Answer 2

Answer:

construction of triangle is not possible

Step-by-step explanation:

Draw a triangle pqr in which pq=7, qr = 3cm and rp = 4 CM. is the construction of triangle possible?

pq = 7 cm

qr = 3 cm

rp = 4cm

3 + 4  = 7

qr + rp = pq

for a triangle Sum of any two sides > third side

Also if we calculate area of this triangle

S = (3 + 4 + 7)/2 = 7

Area = √7(7-3)(7-4)(7-7) = √ 7 * 3 * 4 * 0 = 0

Area of Triangle is Zero

it means all point will lie on the same line

so construction of triangle is not possible