draw a triangle PQR in which QR is equals to 3.5 cm and angle q is equals to 40 degree and angle r is equal to 60 degree
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Answer:
Steps of construction;
- Draw the base OR =3.5 cm
- At Q construct 40 degrees with protractor
- Draw a line through it i.e QY
- At R construct 60 degrees with a compass
- Draw a line through it i.e RX
- Join both the lines and name the point of incidence P
(refer to the pic above)
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The construction of ∆PQR is attached.
Given:
- A triangle PQR.
- QR is equals to 3.5 cm and angle Q=40° and angle R=60°.
To find:
- Construction of ∆ PQR.
Solution:
Steps of construction:
- Draw base line QR,3.5 cm in length with the help of scale and pencil.
- Measure some length with compass and make an arc form point R, mark another arc on that arc from base line, it is angle measure 60°.
- With the help of protector mark an angle of 40° from point Q.
- The rays of both angles meet at a point, let this point is P.
- Construction of ∆PQR is over.
Thus,
By this way construction of ∆PQR is done according to the given specifications.
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Learn more:
1) Construct ΔPQR such that QR = 6 cm,∠Q=∠R=60°. Measure the other two sides of the triangle and name the triangle.
https://brainly.in/question/4836002
2) Draw an obtuse angled Δ LMN. Draw its altitudes and denote the orthocentre by ‘O’.
https://brainly.in/question/4730706
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