Draw a triangleABC with sides BC= 7cm angleB=45°
A=105°
then construct a triangle whose sides are4/3 times the coresponding sides of triangleABC
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Sum of all side of triangle = 180°
∴ ∠A + ∠B + ∠C = 180°
∠C = 180° - 150° = 30°
Steps of Construction:
Step I: BC = 7 cm is drawn.
Step II: At B, a ray is drawn making an angle of 45° with BC.
Justification:
∠B = 45° (Common)
∠C = ∠C'
ΔAB'C' ~ ΔABC by AA similarity condition.
∴ BC/BC' = AB/A'B' = AC/A'C'
also,
BC/BC' = BB3/BB4 = 34
⇒ AB = 4/3 AB', BC = 4/3 BC' and AC = 4/3 A'C'
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