What minimum force F is required to keep a 5kg block at rest on an inclined plane of inclination30 °. The coefficient of static friction between the block and the inclined plane is 0.25.
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When body is at rest on inclined plane,
required force will be equal to the
sinθ component of the weight
F = mgsinθ
F = 5×10×sin30
F = 5×10×12
F = 25 N
required force will be equal to the
sinθ component of the weight
F = mgsinθ
F = 5×10×sin30
F = 5×10×12
F = 25 N
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