Question

Draw a velocity-time graph from the data given below: a) What type of motion is represented during 0-6 second? b) What is the acceleration in the first 6 seconds? c) Using graph, calculate the distance travelled between 6 to 8 seconds. d) Calculate retardation during 12-14 seconds

Answer 1

Answer:

hey dude i just want to correct a small error

The last answer is not 5 metre per second square..... it is negative 5 metre per second square

Since final velocity is less than initial velocity and

a= (v-u ) ÷ t

Answer 2

Given:

Table of time Vs velocity

To Find:

To draw the graph and find the distance travelled between 6 - 8 seconds

Explanation:

Uniform Accelerated motion = 2.5 m/s⁻²

Distance travelled = area covered (i.e. the area of trapezium formed)
= 35 m

The graph for the above question is attached in the image below

Therefore distance travelled = 35 m.