Math, asked by dalvisshrawani2008, 1 month ago

Draw AACD using SSS construction (Fig 4.11). (We now need to find B at a distance of 4.5 cm from C and 7 cm from D).
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Answers

Answered by roybarmansan
3

Answer:

1. Draw AD of length 6 cm.

2. Cut an arc of 7 cm from A and 4 cm from D. Their point of intersection is C.

3. Cut an arc of 4,5 cm from A and 5.5 cm from C. Their point of intersection is B.

4. Join all the points.

ABCD is the required quadrilateral.

2)

1. Draw UM of length 4 cm.

2. Cut an arc of 6.5 cm from U and 5 cm from M. Their point of intersection is P.

3. Cut an arc of 3.5 cm from U and 4.5 cm from P. Their point of intersection is J.

4. Join all the points.

JUMP is the required quadrilateral.

3)

1. Draw OR of length 6 cm.

2. Cut an arc of 7.5 cm from O and 4.5 cm from R. Their point of intersection is E.

3. Cut an arc of 4.5 cm from O and 6 cm from E. Their point of intersection is M.

4. Join all the points.

MORE is the required parallelogram.

4)

1. Draw ET of length 6 cm.

2. Draw its perpendicular bisector.

3. Cut an arc of 4.5 cm from E on the perpendicular bisector both above and below ET, the point of intersections are B and S.

4. Join all the points.

BEST is the required rhombus.

solution

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