Draw △ABC in which AB = 5.5 cm. BC = 6 cm and CA = 7 cm. Also, draw perpendicular bisector of side BC.
Answers
Answer:
Answer in image....
Step-by-step explanation:
Construction:
★ First, draw a line segment AB which is 5.5 cm long.
★ Cut an arc of radius 6 cm from B using a compass.
★ Now, cut another arc of radius 7 cm from C, such that, it intersects the previously drawn arc at C.
★ Draw lines from A to C and B to C, so that it joins AC and BC to obtain the desired triangle.
★ Draw two arcs of radius more than half of BC, keeping B as the centre, on both sides of BC.
★ Similarly, draw two arcs of radius more than half of BC, keeping C as the centre, on both sides of BC such that it intersects the arcs drawn in the previous step at X and Y.
★ By joining XY, we obtain the perpendicular bisector of BC.
Answer:
Answer in image...
Step-by-step explanation:
Step-1 First, draw a line segment AB which is 5.5 cm long.
Step-2 Cut an arc of radius 6 cm from B using a compass.
Step-3 Now, cut another arc of radius 7 cm from C, such that, it intersects the previously drawn arc at C.
Step-4 Draw lines from A to C and B to C, so that it joins AC and BC to obtain the desired triangle.
Step-5 Draw two arcs of radius more than half of BC, keeping B as the centre, on both sides of BC.
Step-6 Similarly, draw two arcs of radius more than half of BC, keeping C as the centre, on both sides of BC such that it intersects the arcs drawn in the previous step at X and Y.
Step-7 By joining XY, we obtain the perpendicular bisector of BC.
