Draw ABC in which/(AC) = 5 cm, M(AB) 4 cm, (BC) = 3.5 cm. Also plot a point D Such that it is at a distance of 5 cm from point A and C. Draw segment AD and segment CD and form DABCD (points B and D are on opposite side of seg AC
Answers
Answer:
Steps of construction are given below :
⇒ Draw line segment BC of length 4.5cm.
⇒ With C as a center and radius CD = 5cm draw an arc.
⇒ With B as a center and radius BD = 7cm draw an arc intersecting the previous arc at D.
⇒ Again with C as the center and 5.5cm as a radius draw an arc.
⇒ Then with D as the center and 5.5cm as radius, draw an arc intersecting the point at A.
⇒ Join AB, AD, CD, BD, and AC.
Thus, ABCD is a required quadrilateral.
Steps of construction are given below :
⇒ Draw line segment BC of length 4.5cm.
⇒ With C as a center and radius CD = 5cm draw an arc.
⇒ With B as a center and radius BD = 7cm draw an arc intersecting the previous arc at D.
⇒ Again with C as the center and 5.5cm as a radius draw an arc.
⇒ Then with D as the center and 5.5cm as radius, draw an arc intersecting the point at A.
⇒ Join AB, AD, CD, BD, and AC.
Thus, ABCD is a required quadrilateral.
Steps of construction are given below :
⇒ Draw line segment BC of length 4.5cm.
⇒ With C as a center and radius CD = 5cm draw an arc.
⇒ With B as a center and radius BD = 7cm draw an arc intersecting the previous arc at D.
⇒ Again with C as the center and 5.5cm as a radius draw an arc.
⇒ Then with D as the center and 5.5cm as radius, draw an arc intersecting the point at A.
⇒ Join AB, AD, CD, BD, and AC.
Thus, ABCD is a required quadrilateral.