Question

Draw ∆ ABC such that, AB = 8 cm, BC = 6 cm and∠B = 90°. Draw seg BD

perpendicular to hypotenuse AC. Draw a circle passing through points

B, D, A. Show that line CB is a tangent of the circle.

Answer 1

Answer:

CB is a tangent of the circle.

Step-by-step explanation:

From the figure attached with this answer, we get triangle ABC is a right angled triangle .

AB = 8 cm, BC = 6 cm and∠B = 90°

BD is perpendicular to hypotenuse

a circle passing through pointsB, D, A.

To prove  CB is a tangent of the circle.

Triangle ABD is a right angled triangle.

The center of circumcircle of a right angled triangle is the mid point of hypotenuse.

Therefore AB is the diameter of the circle.

We have <ABC = 90°

Angle making with a tangent from a point of circle and the radius from that point is 90°.

Here,  <ABC = 90°

Therefore CB is a tangent of the circle.