In the following figure, find the value of x:
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4
since,
BD =AD
angleBAD= 50
angleBDA=180-(50+50)=80
angleADC=180-80=100
ad=dc
therefore,180=100+2x
x =40
hope u understand
BD =AD
angleBAD= 50
angleBDA=180-(50+50)=80
angleADC=180-80=100
ad=dc
therefore,180=100+2x
x =40
hope u understand
Answered by
1
Solution:
It is given that BD= AD
So, angle DBA = angle BAD [ If two sides are equal in a triangle,they make equal angles]
< DBA = < BAD = 50°
Now in Triangle ∆ ABD
< DBA + < BAD + < ADB= 180° [Angle sum property of triangle]
< ADB = 180°-50°-50°
< ADB = 80°
So, < ADB + < ADC = 180°[linear pair]
< ADC = 180°-80° = 100°
It is given that DC= AD
So, < DAC= < DCA = x° [ If two sides are equal in a triangle,they make equal angles]
Now in Triangle ∆ ADC
< ADC + < DCA + < DAC= 180° [Angle sum property of triangle]
100°+2x= 180°
2x=80°
x= 40°
Hope it helps you.
It is given that BD= AD
So, angle DBA = angle BAD [ If two sides are equal in a triangle,they make equal angles]
< DBA = < BAD = 50°
Now in Triangle ∆ ABD
< DBA + < BAD + < ADB= 180° [Angle sum property of triangle]
< ADB = 180°-50°-50°
< ADB = 80°
So, < ADB + < ADC = 180°[linear pair]
< ADC = 180°-80° = 100°
It is given that DC= AD
So, < DAC= < DCA = x° [ If two sides are equal in a triangle,they make equal angles]
Now in Triangle ∆ ADC
< ADC + < DCA + < DAC= 180° [Angle sum property of triangle]
100°+2x= 180°
2x=80°
x= 40°
Hope it helps you.
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