Chemistry, asked by pallavi13913, 3 months ago

draw all the sterioisomer of 2-3 butandiol​

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Answered by diyabhana
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Isomerism. Of the three stereoisomers, two are enantiomers (levo- and dextro-2,3-butanediol) and one is a meso compound. The enantiomeric pair have (2R, 3R) and (2S, 3S) configurations at carbons 2 and 3, while the meso compound has configuration (2R, 3S) or, equivalently, (2S, 3R). be

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