Draw an angle of 70 degree and if the bisectors of angles ABC and ACB of a triangle ABC meet at a point O, then prove that Angle BOC =90°+1÷2angle A.
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I will be using A, B, C not angle A or angle B.... Hope you will not mind it.
As we know A + B + C = 180So, B + C = 180 - AOr, (B/2) + (C/2) = 90 - (A/2) ....(1)
Now think in triangle BOC,we have three angles, OBC, BOC and OCBOBC = (B/2)OCB = (C/2)Let BOC = X
So, X + (B/2) + (C/2) = 180From equation (1)
X + 90 - (A/2) = 180X = 90 + A/2 (Proved !!!)
Hope it help u
plzz mark as brainlist
I will be using A, B, C not angle A or angle B.... Hope you will not mind it.
As we know A + B + C = 180So, B + C = 180 - AOr, (B/2) + (C/2) = 90 - (A/2) ....(1)
Now think in triangle BOC,we have three angles, OBC, BOC and OCBOBC = (B/2)OCB = (C/2)Let BOC = X
So, X + (B/2) + (C/2) = 180From equation (1)
X + 90 - (A/2) = 180X = 90 + A/2 (Proved !!!)
Hope it help u
plzz mark as brainlist
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