Question

draw any one rough graph of ax^2+bx+c=0 ,a is not equal to 0 if b^2>4ac.​

Answer 1

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Draw any one rough graph of 'y=ax²+bx+c'

We are given the 'DISCRIMINANT' of the graph

$D=b^2-4ac>0$

CONCLUSION

The graph is having no intersection at x-axis