draw circle with Centre O and radius 3.5 CM take a point P at a distance of 5.7 cm from the circle draw the tangent to the circle from point P
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1. First of all, we draw a circle of radius AB = 6 cm.
2. Make a point P at a distance of OP = 10 cm, and join OP.
3. Draw a right bisector of P, intersecting OP at Q.
4. Taking Q as center and radius OQ = PQ, draw a circle to intersect the given circle at T and T`.
5. Join PT and PT to obtain the required tangents.
Thus, PT and PT are the required tangents.
Find the length of the tangents.
2
As we know that OT⊥PTandΔOPTOT⊥PTandΔOPT is the right triangle.
Therefore,
OT = 6 cm and PO = 10 cm.
In ΔOPTΔOPT,
PT2=OP2–OT2PT2=OP2–OT2
= (10)2–(6)2(10)2–(6)2
= 100 – 36
= 64
PT = 8 cm
Thus, length of tangents = 8 cm.
Q.2: Draw a circle of radius 3 cm. Take two points P and Q on one of its extended diameter each at a distance of 7 cm from its center. Draw tangents to the circle from these points P and Q.
Solutions:
3
Steps of construction:
(i) Draw a line segment PQ of 14 cm.
(ii) Take the midpoint O of PQ.
(iii) Draw the perpendicular bisectors of PO and OQ which intersects at points R and S.
(iv) With center R and radius RP draw a circle.
(v) With center S and radius, SQ draw a circle.
(vi) With center O and radius 3 cm draw another circle which intersects the previous circles at the points A, B, C, and D.
(vii) Join PA, PB, QC, and QD.
So, PA, PB, QC, and QD are the required tangents.
Q.3: Draw a line segment AB of length 8 cm. Taking A as the center, draw a circle of radius 4 cm and taking B as the center, draw another circle of radius 3 cm. Construct tangents to each circle from the center of the other circle.
Solution.
4
Steps of construction:
(i) Draw a line segment AB of 8 cm.
(ii) Draw the perpendicular of AB which intersects it at C.
(iii) With the center, C and radius CA draw a circle.
(iv) With centers A and B radius 4 cm and 3 cm, draw two circle which intersects the previous at the points P, Q, R and S.
(v) Join AR, AS, BP and BQ
So, AR, AS, BP and BQ are the required tangents.
Q.4: Draw two tangents to a circle of radius 3.5 cm from a point P at a distance of 6.2 cm from its center.
Solution:
Steps of construction:
1. Draw a circle with O as a center and radius 3.5 cm.
2. Mark a point P outside the circle such that OP = 6.2 cm
3. Join OP. Draw the perpendicular bisector XY of OP, cutting OP at Q.
4. Draw a circle with Q as center and radius PQ( or OQ), to intersect the given circle at the points T and T`.
5. Join PT and PT`.
5
Here, PT and PT` are the required tangents.
Q.5: Draw a pair of tangents to a circle of radius 4.5 cm, which are inclined to each other at an angle of 45∘45∘.
Solution:
Steps of Construction:
1. Draw a circle with center O and radius 4.5 cm.
2. Draw any diameter AOB of the circle.
3. Construct ∠BOC=45∘∠BOC=45∘ such that, radius OC cuts the circle at C.
4. Draw AM⊥ABAM⊥AB and CN⊥OCCN⊥OC. Suppose AM and CN intersect each other at P.
6
Here, AP and CP are the pairs of tangents to the circle inclined to each other at an angle of 45circ45circ.
4. Join AC. Thus, ΔABCΔABC is the required triangle.
5. From B, draw BD⊥ACBD⊥AC.
6. Draw the perpendicular bisector of BC, cutting BC at O.
7. With O as center and radius OB ( or OC ), draw a circle. This circle passes through B, C and D.
8. Thus, this is the required circle.
9. Join OA.
10. Draw the perpendicular bisector of OA, cutting OA at E.
11. With E as a center and radius AE ( or OE ), draw a circle intersecting the circle with center O at B and F.
12. Join AF.
2. Make a point P at a distance of OP = 10 cm, and join OP.
3. Draw a right bisector of P, intersecting OP at Q.
4. Taking Q as center and radius OQ = PQ, draw a circle to intersect the given circle at T and T`.
5. Join PT and PT to obtain the required tangents.
Thus, PT and PT are the required tangents.
Find the length of the tangents.
2
As we know that OT⊥PTandΔOPTOT⊥PTandΔOPT is the right triangle.
Therefore,
OT = 6 cm and PO = 10 cm.
In ΔOPTΔOPT,
PT2=OP2–OT2PT2=OP2–OT2
= (10)2–(6)2(10)2–(6)2
= 100 – 36
= 64
PT = 8 cm
Thus, length of tangents = 8 cm.
Q.2: Draw a circle of radius 3 cm. Take two points P and Q on one of its extended diameter each at a distance of 7 cm from its center. Draw tangents to the circle from these points P and Q.
Solutions:
3
Steps of construction:
(i) Draw a line segment PQ of 14 cm.
(ii) Take the midpoint O of PQ.
(iii) Draw the perpendicular bisectors of PO and OQ which intersects at points R and S.
(iv) With center R and radius RP draw a circle.
(v) With center S and radius, SQ draw a circle.
(vi) With center O and radius 3 cm draw another circle which intersects the previous circles at the points A, B, C, and D.
(vii) Join PA, PB, QC, and QD.
So, PA, PB, QC, and QD are the required tangents.
Q.3: Draw a line segment AB of length 8 cm. Taking A as the center, draw a circle of radius 4 cm and taking B as the center, draw another circle of radius 3 cm. Construct tangents to each circle from the center of the other circle.
Solution.
4
Steps of construction:
(i) Draw a line segment AB of 8 cm.
(ii) Draw the perpendicular of AB which intersects it at C.
(iii) With the center, C and radius CA draw a circle.
(iv) With centers A and B radius 4 cm and 3 cm, draw two circle which intersects the previous at the points P, Q, R and S.
(v) Join AR, AS, BP and BQ
So, AR, AS, BP and BQ are the required tangents.
Q.4: Draw two tangents to a circle of radius 3.5 cm from a point P at a distance of 6.2 cm from its center.
Solution:
Steps of construction:
1. Draw a circle with O as a center and radius 3.5 cm.
2. Mark a point P outside the circle such that OP = 6.2 cm
3. Join OP. Draw the perpendicular bisector XY of OP, cutting OP at Q.
4. Draw a circle with Q as center and radius PQ( or OQ), to intersect the given circle at the points T and T`.
5. Join PT and PT`.
5
Here, PT and PT` are the required tangents.
Q.5: Draw a pair of tangents to a circle of radius 4.5 cm, which are inclined to each other at an angle of 45∘45∘.
Solution:
Steps of Construction:
1. Draw a circle with center O and radius 4.5 cm.
2. Draw any diameter AOB of the circle.
3. Construct ∠BOC=45∘∠BOC=45∘ such that, radius OC cuts the circle at C.
4. Draw AM⊥ABAM⊥AB and CN⊥OCCN⊥OC. Suppose AM and CN intersect each other at P.
6
Here, AP and CP are the pairs of tangents to the circle inclined to each other at an angle of 45circ45circ.
4. Join AC. Thus, ΔABCΔABC is the required triangle.
5. From B, draw BD⊥ACBD⊥AC.
6. Draw the perpendicular bisector of BC, cutting BC at O.
7. With O as center and radius OB ( or OC ), draw a circle. This circle passes through B, C and D.
8. Thus, this is the required circle.
9. Join OA.
10. Draw the perpendicular bisector of OA, cutting OA at E.
11. With E as a center and radius AE ( or OE ), draw a circle intersecting the circle with center O at B and F.
12. Join AF.
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