Draw graphs of the equation 3x-y+3=0andx+y-3=0 in the same graph and find the coordinates of the point where two lines intersect.
Answers
ANSWER
We draw graphs of the equations x+y=3 and 3x−2y=4. Then locate their point of intersection.
Recall, that it is enough to know two points to draw a straight line. Consider x+y=3. Taking x=0, we get y=3. Taking y=0, we get x=3. Thus (0,3) and (3,0) are on the straight line x+y=3.
Take a graph paper. Fix your coordinate system x⇔y axis on the graph paper. Locate A=(3,0) and B=(0,3) with respect to this coordinate system.
Join A and B and extend it to a straight line.
Consider the equation 3x−2y=4. If we take x=0, we obtain y=−2. Similarly, x=4 gives y=4. Thus C=(0,−2) and D=(4,4) are points on the straight line 3x−2y=4. Locate these points on the graph paper. Join them and extend to a straight line.
Now we have two straight line. They intersect at a point E. Looking at the graph, you see that E has coordinates (2,1). Thus x=2 and y=1 is the solution. We may verify it: 2+1=3 and 3(2)−2(1)=6−2=4.
