Question

Draw LABC = 75° Bisect it. From a point P on the bisector draw perpendiculars on arms AB and BC
meeting them at D and E respectively. Is PD = PE?​

Answer 1

Steps of construction:

# draw a line BC.

# construct angle ABC=75°

# bisect it

# from point P on the angle

bisector, construct PD _L to AB

and PE _L to BC

# PD=PE, as required.

Diagram in attachment.

HOPE IT HELPS!!

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