Question

draw line segment PQ of 8.5 cm and mark a point a on it such that the P A is equal to 6.5 CM draw a perpendicular to PQ at a​

Answer 1

5 Easy Steps to Construct $\angle$45

Step-by-step explanation:

The Steps of Construction are -

1.) PQ a line segment of length 8.5 cm is being drawn initially.

2.) With P as the center, taking a measurement of 6.5 cm, with the help of a compass, drawn an arc, intersecting PQ at A.

3.) With A as the center and some radius, draw an arc intersecting AP and AL at N and M respectively.

4.) Taking the same radius of the compass, draw two arcs, one from M and other from N, intersecting each other at T.

5.) Join AT, the bisector of $\angle$ PAL, thus resulting in $\angle$TAP = 45.

Answer 2

Step-by-step explanation:

$pq \: a \: line \: segment \: of \: lengeth \: 8.5cm \: is \: being \: drawn \: initially$

$writh \: pas \: the \: center \: taking \: a \: measurement \: of \: 6.5cm writh \: the \: help \: of \: a \: compass \: draw \: an \: are \: intersecting \: pq \: at \: a$

$withe \: a \: as \: the \: center \: and \: same \: radius \: draw \: an \: arc \: intersecting \: ap \: and \: al \: at \: n \: and \: m \: repectively$

$taking \: the \: same \: radius \: of \: the \: compass \: draw \: two \: arcs \: one \: from \: m \: and \: other \: from \: n \: intersecting \: each \: other \: at \: t$

$join \: at \: the \: besector \: of \: < pal \: thus \: reulting \: in \: < tap = 45.$