Draw mirror images of glucose and fructose .
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Sucrose is a disaccharide carbohydrate , that can be hydrolyzed to one mole of glucose and one mole of fructose.
e.g., 1 sucrose -----(H30^+,heat)----> 1 glucose + 1 fructose .
and we also know that glucose and fructose are chiral compounds so, it shows optical isomerism. D - sucrose is mirror image of L - sucrose here The notations D and L are used to describe the configuration of carbohydrates and amino acids.
similarly, D - fructose is mirror image of L - fructose as shown in figure.
e.g., 1 sucrose -----(H30^+,heat)----> 1 glucose + 1 fructose .
and we also know that glucose and fructose are chiral compounds so, it shows optical isomerism. D - sucrose is mirror image of L - sucrose here The notations D and L are used to describe the configuration of carbohydrates and amino acids.
similarly, D - fructose is mirror image of L - fructose as shown in figure.
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We know, p(x)=[g(x)×q(x)]+r(x)
∴p(x)−r(x)=g(x)×q(x)
∴p(x)+{−r(x)}=g(x)×q(x)
It is clear that RHS is divisible by g(x). ∴LHS is also divisible by g(x)
Thus, if we add −r(x) to p(x), then the resulting polynomial is divisible by g(x).
Let us divide p(x)=x
4
+2x
3
−2x
2
+x−1 by g(x)=x
2
+2x−3 to find the remainder r(x).
∴r(x)=−x+2⇒{−r(x)}=x−2
Hence, we should add (x−2) to p(x)=x
4
+2x
3
−2x
2
+x−1 so that the resulting polynomial is exactly divisible by x
2
+2x−3.
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