Draw more than ogive for the following frequency distribution:
Marks 0 – 10 10 – 20 20 – 30 30 – 40 40 – 50 50 – 60
Number of students 5 8 6 10 6 6
also find the median from the graph and verify that by using the formula.
Answers
Answer:
The median of following data is 31.5
Step-by-step explanation:
Marks No. of students Cumulative Frequency
0-10 5 5
10-20 8 5+6=13
20-30 6 13+6=19
30-40 10 19+10=29
40-50 6 29+6=35
50-60 6 35+6=41
Formula:
where, N=total frequency=41/2=20.5 (so the model class is the bold one)
cf (or previous cumulative frequency of model class=19
f (frequency of model class)=10
l (lowest class boundry of model class)=30
h (size of class interval)=10
Putting values in formula,
Ogive is attached as cant be drawn here...
hope u find it helpful :)
Answer:
Marks No. of students Cumulative Frequency
0-10 5 5
10-20 8 5+6=13
20-30 6 13+6=19
30-40 10 19+10=29
40-50 6 29+6=35
50-60 6 35+6=41
Formula:
\begin{lgathered}Median=l+(\frac{\frac{N}{2}-c}{f})h\\\end{lgathered}Median=l+(f2N−c)h
where, N=total frequency=41/2=20.5 (so the model class is the bold one)
cf (or previous cumulative frequency of model class=19
f (frequency of model class)=10
l (lowest class boundry of model class)=30
h (size of class interval)=10
Putting values in formula,
\begin{lgathered}=30+(\frac{\frac{41}{2}-19}{10})*10\\ =30+(\frac{20.5-19}{10})10\\=30+(\frac{1.5}{10})10\\Median =31.5\end{lgathered}=30+(10241−19)∗10=30+(1020.5−19)10=30+(101.5)10Median=31.5