Draw ∆ PQR which is an equilateral triangle of side 4.8 cm. Draw ∆ LMN
similar to ∆ PQR so that the ratio of their corresponding sides is 5:4.
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Answer:
(i) Draw a line segment which is sufficiently long using ruler.
(ii) Locate points A and B on it such that AB=4.8cm.
(iii) With A as centre and radius 4.8cm , draw an arc(see figure)
(iv) With B as centre and radius 4.8cm, draw another arc cutting the previous arc at C.
(v) Join AC and BC Then ABC is the required triangle:
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