Draw ΔPQR with m∠P = 60, m∠Q = 45 and PQ = 6 cm. Then construct ΔPBC whose sides have lengths 5/3 times the lengths of the corresponding sides of ΔPQR
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Answer:
ΔPQR is constructed
Step-by-step explanation:
Step 1 : Draw Line segment PQ = 6 cm using Ruler
Step 2 : Drawn an angle of 60 ° at P using Protector
Step 3 : Draw an angle of 45° at Q using protector
Step 4 : both angle intersect at R
Step 5 : join PR & QR
ΔPQR is constructed
ΔPBC whose sides have lengths 5/3 times the lengths of the corresponding sides of ΔPQR
PB = 6 * 5/3 = 10 cm
Extend PQ to B PB = 10 cm
Extend PR
Draw ║ line to QR passing from X and intersecting extended PR line at C
ΔPBC is constructed
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