Math, asked by adithyaram9307, 11 months ago

Draw ΔPQR with m∠P = 60, m∠Q = 45 and PQ = 6 cm. Then construct ΔPBC whose sides have lengths 5/3 times the lengths of the corresponding sides of ΔPQR

Answers

Answered by amitnrw
0

Answer:

ΔPQR is constructed

Step-by-step explanation:

Step 1 : Draw Line segment PQ = 6 cm using Ruler

Step 2 : Drawn an angle of 60 ° at P using Protector

Step 3 : Draw an angle of 45° at Q using protector

Step 4 : both angle intersect at R

Step 5 : join PR & QR

ΔPQR is constructed

ΔPBC whose sides have lengths 5/3 times the lengths of the corresponding sides of ΔPQR

PB = 6 * 5/3 = 10 cm

Extend PQ to B PB = 10 cm

Extend PR

Draw ║ line to QR passing from X and intersecting extended PR line at C

ΔPBC is constructed

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