Math, asked by devadathan007, 1 month ago

draw quadrilateralwith AB=8cm, BC=6.5cm<A=50°, <B=65°, AD=5cm and then draw a triangle having the area of this quadrilateral​

Answers

Answered by shivushivakumar0012
0

Answer:

Given:

AB = 6.5 cm, AD = 5 cm, CD = 5 cm, ∠ BAC = 40° and ∠ ABC = 50 °.

Steps for construction

Step 1 : Draw a rough diagram and mark the given measurements.

Step 2 : Draw a line segment AB = 6.5cm.

Step 3 : At A on AB make ∠BAX whose measure is 40° and at B on AB make ∠ABY whose measure is

50 ° . They meet at C.

Step 4 : With A and C as centres draw two arcs of radius 5cm and let them cut at D.

Step 5 : Join AD and CD

. ABCD is the required quadrilateral.

Step 6 : From D draw DE⊥ AC and from B draw

BC ⊥ AC

. Then measure the lengths of BC and DE. BC = h 1 = 4.2 cm, DE = h 2

= 4.3 cm and AC = d = 5 cm.

Calculation of area:

In the quadrilateral ABCD, d = 5 cm, h 1

= 4.2 cm and h2

= 4.3 cm.

Area of the quadrilateral ABCD = 21d(h 1+h 2 )

= 21 (57.8)(4.2+4.3)

= 21×5×8.5

=21.25 cm 2

Answered by amitnrw
0

Given :  AB=8cm, BC=6.5cm , ∠A=50°, ∠B=65°, AD=5cm  

To Find :  draw quadrilateral

Solution:

Step 1 :  Draw  a line segment AB = 8 cm

Step 2 :  Draw an angle of 65° at B on AB using protractor

Step 3 : Take a length of 6.5 cm from B on angle drawn  and label  C

Step 4 : Join BC

Step 5 :  Draw an angle of 50° at A on AB using protractor

Step 6 : Take a length of 5 cm from A on angle drawn  and label  D

Step 7 : Join AD

Step 8 : Join BC

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