Question

draw the bond line formula of2-chlroropentane.

and

show that Bef3 molecule has zero dipole moment.

and

mention the factors effecting ionization enthalpy.

Answer 1

Hi mate. 

Thanks for asking this question, 

Here is your answer, 


Given : 

T = 25c = 298k

V = 150 ml. 

n = w/m = 1.95 / 342 = 0.005 moles. 

R = 8.314 J/k.mol.


\pi \: =π= 

We know that, 


\pi \: v \: = \: n \: r \: tπv=nrt 
Therefore, 


\pi \ \times 150 \: = \: 0.005 \times 8.314 \times 298π ×150=0.005×8.314×298 

\begin{lgathered}\pi \: \times 150 = \: 5 \times {10}^{? - 3 } \times 8.314 \times \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 298\end{lgathered}π×150=5×10?−3×8.314×298​ 

\pi \: = \: 0.33 \times {10}^{? - 2} \times 2477.5π=0.33×10?−2×2477.5 

\pi \: = \: 3.3 \times {10}^{? - 3} \times 2477.5π=3.3×10?−3×2477.5 

\pi \: = 8175.98 \: \times {10}^{ - 3} pa.π=8175.98×10−3pa.