Physics, asked by Sivababu2274, 10 months ago

Draw the circuit diagram to determine the characteristics of a pnp transistor in common emitter configuration.

Explain, using I-V characteristics, how the collector current changes with the base current. How can (i) output resistance and (ii) current amplification factor be determined from the IV characteristics?

Answers

Answered by aqibkincsem
11

"Below circuit diagram illustrate about the key characteristics of a p-n-p transistor in common emitter configuration

I-V characteristics are drawn by plotting current in the Y-axis and Voltage in the X-axis.

Output resistance:

This is the ratio of collector emitter voltage to the change in collector current that is having a constant current base.

R =V/Ic*Ib

Current amplification factor:

This is defined as the ration of change in the collector change to the change in the base current.

Amplification factor = IC/Ib"

Answered by mindfulmaisel
1

"Given:  

PNP Transistor in CE (Common Emitter configuration)

Solution:

I-V characteristics are drawn by plotting current in the Y-axis and voltage in the X-axis.

Output resistance:

The output resistance is directly propotional to the collector emitter voltage and irsely propotional to the collector current change that is having a constant current base.

R = \frac{V}{I_{C}} \times I_{B}

Current amplification factor:

It usually defined as the ratio of collector current and the base current .

Amplification factor = \frac{I_{C}}{I_{B}}"

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