draw the electronic configuration of HNO3 and justify the + 5 oxidation number
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Explanation:
See the net charge on the compound is 0. Let the oxidation state of N be x. We know that the oxidation state of H is +1 because it is the most electropositive here and it shows -1 state only when the other elements are more electropositive. Now O has an oxidation state of -2 in 99% cases.
So we solve like this ,
Sum of all individual oxidation states = net oxidation state of the compound
So +1 + x - 6 =0
Giving x=5
Hope this helps
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