Question

draw the following graph of linear equation in two variable and solve them 2x+3y+4=0 9x-3y+5=0​

Answer 1

Solution of 2x+3y+4=0, 9x-3y+5=0 is x = -11/9, y= -26/33

• Given,
• 2x+3y+4=0
• 9x-3y+5=0
• add both the equations.
• y coefficient gets cancelled
• we get,
• $x=-\dfrac{9}{11}$
• substitute the value of x in any one of the above equations, we get,
• $y=-\dfrac{26}{33}$

Answer 2

The solution is $(-0.818,-0.788)$

Explanation:

The two equations are $2 x+3 y+4=0$ and $9 x-3 y+5=0$

Solving the two equations using elimination method, we have,

Adding both the equations, we have,

$2 x+3 y+4=0\\ 9x -\ 3y + 5 = 0 \\--------\\7x +9=0$

Simplifying, we have,

$\begin{aligned} 7 x+9 &=0 \\ 7 x &=-9 \\ x &=-0.818 \end{aligned}$

Substituting the value of x in $2 x+3 y+4=0$, we get,

$\begin{aligned} 2(-0.818)+3 y+4 &=0 \\-1.636+3 y+4 &=0 \\ 3 y+2.364 &=0 \\ y &=-0.788 \end{aligned}$

Thus, the solution is $(-0.818,-0.788)$

The attached graph below shows the solution of the equation:

Learn more:

(1) brainly.in/question/15083850

(2) brainly.in/question/4936034