Question

Draw the given polyinomial and find the zoroes P(x)=x2-6x+9

Answer 1

Answer:

${x}^{2} - 6x + 9 = 0 \\ {x}^{2} - (3 + 3)x + ( 3 \times 3) = 0 \\ {x}^{2} - 3x - 3x + (3 \times 3) = 0 \\ {x}^{} (x - 3) - 3(x - 3) = 0 \\ (x - 3)(x - 3) = 0 \\ there \: are \: only \: one \: zeroes \\ = 3$