Question

draw the graph for the equation-2x +y-7=0.ceck whether the point (-3,-2lie on the given line.​

Answer 1

Given :  -2x + y - 7  = 0  

To Find : Draw graph

Check whether point ( - 3, - 2 ) lies on line or not

Solution:

 -2x + y - 7  = 0  

=> -2x + y  = 7

=> --2x/7  +  y/7 = 1

=> x /(-7/2)  + y/7  = 1

Hence two points are  (  -7/2 , 0)  and (  0 , 7)

check (-3 , - 2)

-2(-3) + (-2) - 7  = 6 - 2 - 7  =  - 3 ≠ 0

Hence point does not lie on line

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Answer 2

Step-by-step explanation:

Given: -2x+y-7=0

To find: Draw the graph for the equation

-2x +y-7=0. check whether the point (-3,-2) lie on the given line.

Solution:

Find at least two points of the line

Step 1: Put x=0 in equation

$- 2(0) + y - 7 = 0 \\ y = 7$

One point is (0,7)

Step 2: Put y=0

$- 2x + 0 - 7 = 0 \\ \\ - 2x = 7 \\ \\ x = - 3.5$

Second point is (-3.5, 0)

Step 3: Plot these points in graph and plot the line of equation -2x+y-7=0

Step 4: Checking for point (-3,-2),put the value x= -3 and y= -2 in the equation

$- 2x + y - 7 \\ \\ = - 2( - 3) + ( - 2) - 7 \\ \\ = 6 - 2 - 7 \\ \\ = 6 -9 \\ \\ = - 3 \\ \\ \neq \: 0$

Thus, the point (-3,-2) does not lies on the line.

Final answer:

1) -2x+y-7=0 is plotted and attatched.

2) (-3,-2) does not lies on the line.

Hope it helps you.

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