Draw the graph of 2y- 3x+4-0, y=3 and x =6. Identify the figure
formed by intersection of above lines and x-axis. Find its area.
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Given : 2y- 3x+4=0, y=3 and x =6
To find : Draw the graph Identify the figure formed by intersection of above lines
Find its area.
Solution:
y= 3
x= 6
intersection points (6,3)
2y-3x +4 = 0
y= 3
x = 10/3
(10/3 , 3)
2y-3x +4 = 0
x= 6
y = 7
(6, 7)
Right angle triangle is formed
all points are above x axis only
Area
(1/2) × (6 -10/3))(7 - 3)
= (1/6)(8)(4)
= 32/6
= 16/3
= 5.33
2y-3x +4 = 0
x y
-6 -11
-4 -8
-2 -5
0 -2
2 1
4 4
6 7
8 10
Learn more:
draw graph of the following eq in two variable x+y=5x-y=32(x-1)+3y ...
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(i) Draw the graphs of 2x + y = 6 and y = 2x + 2 intersecting Xand Y ...
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