Question

Draw the graph of linear equation 7x+5y=35 find the point where ts graph meets the line parallel to x-axis and 3 units above it

Answer 1

it is a straight line

Answer 2

Lines 7x+5y=35 and the line parallel to x-axis and 3 units above it, meets at (2.9,3).

Step-by-step explanation:

Given:

• Linear equation $7x + 5y = 35$

To find:

• Draw the graph of linear equation 7x+5y=35.
• Find the point where ts graph meets the line parallel to x-axis and 3 units above it.

Solution:

Concept to be used:

• Find at least two solution/points of linear equation to draw the line.
• Draw a line parallel to x-axis and 3 units above it.
• Find the point of intersection of both lines.

Step 1:

Draw the line 7x+5y= 35.

Put x= 0

$7(0) + 5y = 35$

or

$5y = 35$

or

$\bf y = 7$

One point is (0,7)

Put y=0

$7x + 5(0) = 35$

or

$7x = 35$

or

$\bf x = 5$

Another point is (5,0).

Plot these points and draw the straight line.

Step 2:

Draw line y=3.

A line which is parallel to x-axis is given by by=c.

Because in the question, it is given that it is above x-axis, and 3 units apart.

So,

Equation of line is y=3.

Step 3:

Find the point of intersection of both lines.

It is clear from the attached figure, that both lines meet at (2.9,3).

Point of intersection can be calculated as shown below:

Put y=3 in the equation 7x+5y=35.

$7x + 5(3) = 35$

or

$7x = 35-15$

or

$x = \frac{20}{7}$

or

$\bf x=2.85$

or

x≈2.9

Thus,

Lines 7x+5y=35 and y=3 meets at (2.9,3).

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