Draw the graph of P(x)=x^(2)-5x+6. Hence find its zeroes
please do In graph paper
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( identity : (a-b)² = a²-2ab +b²)
= {(2x - 5y)}^{2}=(2x−5y)
2
= {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x)
2
−2(2x)(5y)+(5y)
2
= 4 {x}^{2} - 20xy + 25 {y}^{2}=4x
2
−20xy+25y
2
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