Draw the
graph of p(x)=x²-6x +9 and find zeroes
Justify
the answer
Answers
Answered by
0
Step-by-step explanation:
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Answered by
1
Answer:
Method 1: using middle term
factorisation
solution:
=>x²–6x+9=0
=>x²–3x–3x+9=0
=>x(x–3)–3(x–3)=0
=>(x–3)(x–3)=0
So x=3 and x=3 are the zeros of of quadratic
equation x²-6x +9.
verification:
=(x–3)(x–3)
=x(x–3)–3(x–3)
=x²–3x–3x+9
=x²–6x+9
2nd method: using formula (a–b)²=a²+b²–2ac
=>x²-6x +9 =0
=>(x)²+(3)²–2×x×3=0
=>(x–3)²=0
=>(x–3)(x–3)=0
=>x=3 and x=3 are the zeros of quadratic equation x²-6x +9
verification:
=(x–3)(x–3)
=(x)²+(3)²–2×x×3
=(x–3)²
So first you must equate both the equations with zero in order to obtain the zeros which
I have done in both the methods and then for verification you must use find the product of zero single variable equation to verify the answer, also the graph is the the equation
is attached please check.
Attachments:
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